linked list - simple adding and deleting in between - for my reference

#include "stdio.h"
#include "stdlib.h"

struct node {
   
   int   data;
   struct node* next;
};

int length(struct node *head){
    
    struct node* current = head;
    int count = 0;
    while ( current != NULL ){
          
          count++;
          current = current -> next;
    }
return count;
}

void display(struct node *head) {
     
      
    struct node* current = head;
    int count = 0;
    while ( current != NULL ){
          
          printf("%d \t", current -> data);
          current = current -> next;
    } 
    printf("\n \n");
}

void delete ( struct node* head, int pos) {
     
     int k = 0;
     struct node* current = head;
     for( k = 0; k < pos; k++){
          
          current = current -> next;
     }
     current -> next = current -> next -> next;
}

void add ( struct node* head, int pos, int data) {
     
     int k = 0;
     struct node* current = head;
     struct node* newNode = malloc(sizeof(struct node));
     for( k = 0; k < pos; k++){
          
         current = current -> next;
     }
     
     newNode -> next = current -> next;
     newNode -> data = data;
     current -> next = newNode;
}         
     
int main(){

    int k = 0;
    int m = 0;
    int i =0;
    int pos = 3;
    struct node* head = NULL;
    struct node* current = NULL;
    struct node* nextCur = NULL;
    
    head = malloc (sizeof (struct node));
    current = malloc (sizeof (struct node));
    head -> data = 1;
    head -> next = current;
    current -> next = NULL;
    
    for(i = 0; i < 5; i++){  
          
         current -> data = i;
         nextCur = malloc (sizeof (struct node));
         current -> next = nextCur;
         current = nextCur;
     }
   current -> data = i; 
   current -> next = NULL; 
      
   display(head);    
   
   delete (head, pos);
   
   display(head);   
   
   add (head, pos, 10); 
   
   display(head); 
    
getch();
return 0;
}